12q^2+25q+12=

Solution for 12q^2+25q+12= equation:

Simplifying
12q2 + 25q + 12 = 0

Reorder the terms:
12 + 25q + 12q2 = 0

Solving
12 + 25q + 12q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(4 + 3q)(3 + 4q) = 0

Subproblem 1
Set the factor '(4 + 3q)' equal to zero and attempt to solve:

Simplifying
4 + 3q = 0

Solving
4 + 3q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 3q = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 3q = 0 + -4
3q = 0 + -4

Combine like terms: 0 + -4 = -4
3q = -4

Divide each side by '3'.
q = -1.333333333

Simplifying
q = -1.333333333
Subproblem 2
Set the factor '(3 + 4q)' equal to zero and attempt to solve:

Simplifying
3 + 4q = 0

Solving
3 + 4q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 4q = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 4q = 0 + -3
4q = 0 + -3

Combine like terms: 0 + -3 = -3
4q = -3

Divide each side by '4'.
q = -0.75

Simplifying
q = -0.75
Solution
q = {-1.333333333, -0.75}